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What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

Option :

Explanation:

Solution:
$\begin{array}{rl}& \text{Length}\phantom{\rule{thinmathspace}{0ex}}\text{of}\phantom{\rule{thinmathspace}{0ex}}\text{largest}\phantom{\rule{thinmathspace}{0ex}}\text{tile}=\\ & \text{H}\text{.C}\text{.F}\text{.}\phantom{\rule{thinmathspace}{0ex}}\text{of}\phantom{\rule{thinmathspace}{0ex}}1517\phantom{\rule{thinmathspace}{0ex}}cm\phantom{\rule{thinmathspace}{0ex}}\text{and}\phantom{\rule{thinmathspace}{0ex}}902\phantom{\rule{thinmathspace}{0ex}}cm=41\phantom{\rule{thinmathspace}{0ex}}cm\\ & \text{Area}\phantom{\rule{thinmathspace}{0ex}}\text{of}\phantom{\rule{thinmathspace}{0ex}}\text{each}\phantom{\rule{thinmathspace}{0ex}}\text{tile}=\left(41×41\right)c{m}^{2}\\ & \therefore \text{Required}\phantom{\rule{thinmathspace}{0ex}}\text{number}\phantom{\rule{thinmathspace}{0ex}}\text{of}\phantom{\rule{thinmathspace}{0ex}}\text{tiles}\\ & =\left(\frac{1517×902}{41×41}\right)\\ & =814\end{array}$