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If
x=3+131
  and
y=313+1,
  then the value of
(x2+y2)
  is?

Option :

Answer:Option 1

Explanation:

Solution:
x=(3+1)(31)×(3+1)(3+1)=(3+1)2(31)=3+1+232=2+3y=(31)(3+1)×(31)(31)=(31)2(31)=3+1232=23x2+y2=(2+3)2+(23)2=2(4+3)=14



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