India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam
  • Sign Up
  • Login
  • 0
  • Donate Now

A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

Option :

Answer:Option 1

Explanation:

Solution:
Totalnumberofballs=(2+3+2)=7.LetSbethesamplespace.Then,n(S)=Numberofwaysofdrawing2ballsoutof7=7C2=(7×6)(2×1)=21.LetE = Eventofdrawing2balls,noneofwhichisblue.n(E)=Numberofwaysofdrawing2ballsoutof(2 + 3)balls=5C2=(5×4)(2×1)=10.P(E)=n(E)n(S)=1021.



Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.

Current Affairs
Test
Classes
E-Book