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# Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?

Option :

Explanation:

Solution:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
$\begin{array}{rl}& \therefore n\left(E\right)=27\\ & \therefore P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}\\ & =\frac{27}{36}=\frac{3}{4}\end{array}$