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In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:

Option :

Answer:Option 1

Explanation:

Solution:
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S) = Number ways of selecting 3 students out of 25.
=25C3=(25×24×23)(3×2×1)=2300.n(E)=(10C1×15C2)=[10×(15×14)(2×1)]=1050.P(E)=n(E)n(S)=10502300=2146.



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