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Problems on Trains
1.A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

Answer:Option 1

Explanation:

Solution:
Speed=(60×518)m/sec=(503)m/secLengthofthetrain=(Speed×Time)Lengthofthetrain=(503×9)m=150m

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2.A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

Answer:Option 1

Explanation:

Solution:
Speedofthetrainrelativetoman=(12510)m/sec=(252)m/sec=(252×185)km/hr=45km/hrLetthespeedofthetrainbexkm/hr.Then,relativespeed=(x5)km/hrx5=45x=50km/hr

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3.The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

Answer:Option 1

Explanation:

Solution:
Speed=(45×518)m/sec=(252)m/secTime=30secLetthelengthofbridgebexmetresThen,130+x30=2522(130+x)=750x=245m

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4.A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

Answer:Option 1

Explanation:

Solution:
Speed=(54×518)m/sec=15m/secLengthofthetrain=(15×20)m=300mLetthelengthoftheplatformbexmetresThen,x+30036=15x+300=540x=240m

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5.A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

Answer:Option 1

Explanation:

Solution:
Speed=(24024)m/sec=10m/secRequiredtime = (240+65010)sec.=89sec.

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6.Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

Answer:Option 1

Explanation:

Solution:
Letthelengthofeachtrainbexmetres.Then,distancecovered=2xmetres.Relativespeed=(4636)km/hr=(10×518)m/sec=(259)m/sec2x36=2592x=100x=50

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7.A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

Answer:Option 1

Explanation:

Solution:
Formulaforconvertingfromkm/hrtom/s:Xkm/hr=(X×518)m/sTherefore,Speed=(45×518)m/sec=252m/secTotaldistancetobecovered=(360+140)m=500mFormulaforfindingTime=(DistanceSpeed)Requiredtime=(500×225)sec=40sec.

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8.A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

Answer:Option 1

Explanation:

Solution:
Speedoftrainrelativetojogger=(459)km/hr=36km/hr(36×518)m/sec=10m/secDistancetobecovered=(240+120)m=360mTimetaken=(36010)sec=36sec

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9.A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

Answer:Option 1

Explanation:

Solution:
Relativespeed=(120+80)km/hr=(200×518)m/sec=(5009)m/secLetthelengthoftheothertrainbexmetres.Then,x+2709=5009x+270=500x=230

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10.A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

Answer:Option 1

Explanation:

Solution:
Speed=(72×518)m/sec=20m/secTime=26secLetthelengthofthetrainbexmetres.Then,x+25026=20x+250=520x=270

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