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Races-and-Games
1.In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:

Answer:Option 1

Explanation:

Solution:
A:B=100:90A:C=100:72B:C=BA×AC=90100×10072=9072
When B runs 90 m, C runs 72 m.
When B runs 100m, C run
(7290×100)m=80m
∴ B can give C 20m

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2.A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:

Answer:Option 1

Explanation:

Solution:
Asspeed=(5×518)m/sec=2518m/secTimetakenbyAtocover100m=(100×1825)sec=72secTimetakenbyBtocover92m=(72+8)=80secBsspeed=(9280×185)kmph=4.14kmph

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3.In a 500 m race, the ratio of the speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then, A wins by:

Answer:Option 1

Explanation:

Solution:
To reach the winning post A will have to cover a distance of (500 - 140)m, i.e., 360 m.
While A covers 3 m, B covers 4 m.
While A covers 360 m, B covers (4/3 * 360) m = 480 m.
Thus, when A reaches the winning post, B covers 480 m and therefore remains 20 m behind.
∴ A wins by 20 m.

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4.At a game of billiards, A can give B 15 points in 60 and A can give C to 20 points in 60. How many points can B give C in a game of 90?

Answer:Option 1

Explanation:

Solution:
A:B=60:45A:C=60:40BC=(BA×AC)=(4560×6040)=4540=9080=90:80BcangiveC10pointsinagameof90

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5.In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:

Answer:Option 1

Explanation:

Solution:
A:B=200:169A:C=200:182CB=(CA×AB)=(182200×200169)=182:169WhenCcovers182m,Bcovers169mWhenCcovers350m,Bcovers(169182×350)m=325mTherefore,CbeatsBby(350325)m=25m

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6.In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:

Answer:Option 1

Explanation:

Solution:
DistancecoveredbyBin9sec=(10045×9)m=20mAbeatsBby20metres

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7.In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:

Answer:Option 1

Explanation:

Solution:
A:B=100:80A:C=100:72BC=(BA×AC)=(80100×10072)=109=10090=100:90BcangiveC10points

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8.A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:

Answer:Option 1

Explanation:

Solution:
WhenBruns25m,Aruns452mWhenBruns1000m,Aruns=(452×125×1000)m=900mBbeatsAby100m

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9.In a 300 m race A beats B by 22.5 m or 6 seconds. B's time over the course is:

Answer:Option 1

Explanation:

Solution:
Bruns452min6secBcovers300min(6×245×300)sec=80sec

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10.A runs 12/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?

Answer:Option 1

Explanation:

Solution:
RatioofspeedsofAandB=53:1=5:3Thus,inraceof5m,Agains2moverB2maregainedbyAinaraceof5m80mwillbegainedbyAinaraceof(52×80)m=200mWinningpostis200mawayfromthestartingpoint

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