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Rs. 1200 is lent out at 5% per annum simple interest for 3 years. Find the amount after 3 years.

1Rs. 1380
2Rs. 1290
3Rs. 1470
4Rs.1200

Answer:- 1

Explanation:-

Solution:

\begin{aligned} A = P + I \\ A = 1200 + (\frac{P T R}{100}) \\ A = [1200 + (\frac{1200 \times 5 \times 3}{100})] \\ Amount, A = R s . 1380 \end{aligned}

$\eqalign{ & A = P + I \cr & A = 1200 + \left( {\frac{{PTR}}{{100}}} \right) \cr & A = \left[ {1200 + \left( {\frac{{1200 \times 5 \times 3}}{{100}}} \right)} \right] \cr & {\text{Amount}},\,A = Rs.\,1380 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} A = P + I \\ A = 1200 + (\frac{P T R}{100}) \\ A = [1200 + (\frac{1200 \times 5 \times 3}{100})] \\ Amount, A = R s . 1380 \end{aligned}

$\eqalign{ & A = P + I \cr & A = 1200 + \left( {\frac{{PTR}}{{100}}} \right) \cr & A = \left[ {1200 + \left( {\frac{{1200 \times 5 \times 3}}{{100}}} \right)} \right] \cr & {\text{Amount}},\,A = Rs.\,1380 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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