(x−1)2−−−−−−−√ + (x−3)2−−−−−−−√ is?(x−1)2 + (x−3)2 is?\sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {x - 3} \right)}^2}} {\text{ is?}}" /> (x−1)2−−−−−−−√ + (x−3)2−−−−−−−√ is?(x−1)2 + (x−3)2 is?\sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {x - 3} \right)}^2}} {\text{ is?}}" /> (x−1)2−−−−−−−√ + (x−3)2−−−−−−−√ is?(x−1)2 + (x−3)2 is?\sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {x - 3} \right)}^2}} {\text{ is?}}" />

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If 1 < x < 2, then the value of $\sqrt{{(x - 1)}^{2}} + \sqrt{{(x - 3)}^{2}} is?$ $\sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {x - 3} \right)}^2}} {\text{ is?}}$

11
22
33
42x - 4

Answer:- 1

Explanation:-

Solution:

\begin{aligned} 1 < x < 2 \\ \sqrt{{(x - 1)}^{2}} + \sqrt{{(x - 3)}^{2}} \\ (Square root cancel with square) \\ ∴ x - 1 + 3 - x \\ = 2 \end{aligned}

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", "text": "If 1 < x < 2, then the value of

\sqrt{{(x - 1)}^{2}} + \sqrt{{(x - 3)}^{2}} is?

$\sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {x - 3} \right)}^2}} {\text{ is?}}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 1 < x < 2 \\ \sqrt{{(x - 1)}^{2}} + \sqrt{{(x - 3)}^{2}} \\ (Square root cancel with square) \\ ∴ x - 1 + 3 - x \\ = 2 \end{aligned}

$\eqalign{ & 1 < x < 2 \cr & \sqrt {{{\left( {x - 1} \right)}^2}} {\text{ + }}\sqrt {{{\left( {x - 3} \right)}^2}} \cr & \left( {{\text{Square root cancel with square}}} \right) \cr & \therefore x - 1 + 3 - x \cr & = 2 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: