Explanation:-
Solution:
Side of the first square is 4 cm.side of second square=22–√cmSideofthirdsquare=2cmandsoon.i.e.4,2,2–√,2–√,1.......Thus, area of these square will be,=16,8,4,2,1,12........Hence, Sum of the area of first, second, third square....=16+8+4+2+1+......=[16{1−(12)}]=32cm2
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