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A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:

1145º
2150º
3155º
4160º

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Angle traced by hour hand in 12 h r s = 360^{\circ} \\ Angle traced by hour hand in 5 h r s 10 min . i . e ., \\ \frac{31}{6} h r s = {(\frac{360}{12} \times \frac{31}{6})}^{\circ} = 155^{\circ} \end{aligned}

$\eqalign{ & {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,12\,hrs = {360^ \circ } \cr & {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,5\,hrs\,10\,\min .\,i.e., \cr & \frac{{31}}{6}hrs = {\left( {\frac{{360}}{{12}} \times \frac{{31}}{6}} \right)^ \circ } = {155^ \circ } \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Angle traced by hour hand in 12 h r s = 360^{\circ} \\ Angle traced by hour hand in 5 h r s 10 min . i . e ., \\ \frac{31}{6} h r s = {(\frac{360}{12} \times \frac{31}{6})}^{\circ} = 155^{\circ} \end{aligned}

$\eqalign{ & {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,12\,hrs = {360^ \circ } \cr & {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,5\,hrs\,10\,\min .\,i.e., \cr & \frac{{31}}{6}hrs = {\left( {\frac{{360}}{{12}} \times \frac{{31}}{6}} \right)^ \circ } = {155^ \circ } \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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