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The diagonal of the floor of a rectangular closet is 7 ¹/₂ feet. The shorter side of the closet is 4 ¹/₂ feet. What is the area of the closet in square feet?

15 ¹/₄
213 ¹/₂
327
437

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Outer Side \\ = \sqrt{{(\frac{15}{2})}^{2} - {(\frac{9}{2})}^{2}} f t \\ = \sqrt{\frac{225}{4} - \frac{81}{4} f t} \\ = \sqrt{\frac{144}{4} f t} \\ = 6 f t \\ ∴ Area of closet = (6 \times 4.5) s q . f t = 27 s q . f t . \end{aligned}

$\eqalign{ & {\text{Outer}}\,{\text{Side}} \cr & = \sqrt {{{\left( {\frac{{15}}{2}} \right)}^2} - {{\left( {\frac{9}{2}} \right)}^2}} ft \cr & = \sqrt {\frac{{225}}{4} - \frac{{81}}{4}ft} \cr & = \sqrt {\frac{{144}}{4}ft} \cr & = 6ft \cr & \therefore {\text{Area}}\,{\text{of}}\,{\text{closet}} = \left( {6 \times 4.5} \right)sq.\,ft = 27\,sq.\,ft. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Outer Side \\ = \sqrt{{(\frac{15}{2})}^{2} - {(\frac{9}{2})}^{2}} f t \\ = \sqrt{\frac{225}{4} - \frac{81}{4} f t} \\ = \sqrt{\frac{144}{4} f t} \\ = 6 f t \\ ∴ Area of closet = (6 \times 4.5) s q . f t = 27 s q . f t . \end{aligned}

$\eqalign{ & {\text{Outer}}\,{\text{Side}} \cr & = \sqrt {{{\left( {\frac{{15}}{2}} \right)}^2} - {{\left( {\frac{9}{2}} \right)}^2}} ft \cr & = \sqrt {\frac{{225}}{4} - \frac{{81}}{4}ft} \cr & = \sqrt {\frac{{144}}{4}ft} \cr & = 6ft \cr & \therefore {\text{Area}}\,{\text{of}}\,{\text{closet}} = \left( {6 \times 4.5} \right)sq.\,ft = 27\,sq.\,ft. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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