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What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

1814
2820
3840
4844

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Length of largest tile = \\ H .C .F . of 1517 c m and 902 c m = 41 c m \\ Area of each tile = (41 \times 41) c m^{2} \\ ∴ Required number of tiles \\ = (\frac{1517 \times 902}{41 \times 41}) \\ = 814 \end{aligned}

$\eqalign{ & {\text{Length}}\,{\text{of}}\,{\text{largest}}\,{\text{tile}} = \cr & {\text{H}}{\text{.C}}{\text{.F}}{\text{.}}\,{\text{of}}\,1517\,cm\,{\text{and}}\,902\,cm = 41\,cm \cr & {\text{Area}}\,{\text{of}}\,{\text{each}}\,{\text{tile}} = \left( {41 \times 41} \right)c{m^2} \cr & \therefore {\text{Required}}\,{\text{number}}\,{\text{of}}\,{\text{tiles}} \cr & = \left( {\frac{{1517 \times 902}}{{41 \times 41}}} \right) \cr & = 814 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Length of largest tile = \\ H .C .F . of 1517 c m and 902 c m = 41 c m \\ Area of each tile = (41 \times 41) c m^{2} \\ ∴ Required number of tiles \\ = (\frac{1517 \times 902}{41 \times 41}) \\ = 814 \end{aligned}

$\eqalign{ & {\text{Length}}\,{\text{of}}\,{\text{largest}}\,{\text{tile}} = \cr & {\text{H}}{\text{.C}}{\text{.F}}{\text{.}}\,{\text{of}}\,1517\,cm\,{\text{and}}\,902\,cm = 41\,cm \cr & {\text{Area}}\,{\text{of}}\,{\text{each}}\,{\text{tile}} = \left( {41 \times 41} \right)c{m^2} \cr & \therefore {\text{Required}}\,{\text{number}}\,{\text{of}}\,{\text{tiles}} \cr & = \left( {\frac{{1517 \times 902}}{{41 \times 41}}} \right) \cr & = 814 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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