4a2−4a+1−−−−−−−−−−√+3a4a2−4a+1+3a\sqrt {4{a^2} - 4a + 1} + 3a is:" /> 4a2−4a+1−−−−−−−−−−√+3a4a2−4a+1+3a\sqrt {4{a^2} - 4a + 1} + 3a is:" /> 4a2−4a+1−−−−−−−−−−√+3a4a2−4a+1+3a\sqrt {4{a^2} - 4a + 1} + 3a is:" />

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If a = 0.1039, then the value of $\sqrt{4 a^{2} - 4 a + 1} + 3 a$ $\sqrt {4{a^2} - 4a + 1} + 3a$ is:

10.1039
20.2078
31.1039
42.1039

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \sqrt{4 a^{2} - 4 a + 1} + 3 a \\ = \sqrt{{(1)}^{2} + {(2 a)}^{2} - 2 \times 1 \times 2 a} + 3 a \\ = \sqrt{{(1 - 2 a)}^{2}} + 3 a \\ = (1 - 2 a) + 3 a \\ = (1 + a) \\ = (1 + 0.1039) \\ = 1.1039 \end{aligned}

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is:", "text": "If a = 0.1039, then the value of

\sqrt{4 a^{2} - 4 a + 1} + 3 a

$\sqrt {4{a^2} - 4a + 1} + 3a$ is:", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \sqrt{4 a^{2} - 4 a + 1} + 3 a \\ = \sqrt{{(1)}^{2} + {(2 a)}^{2} - 2 \times 1 \times 2 a} + 3 a \\ = \sqrt{{(1 - 2 a)}^{2}} + 3 a \\ = (1 - 2 a) + 3 a \\ = (1 + a) \\ = (1 + 0.1039) \\ = 1.1039 \end{aligned}

$\eqalign{ & \sqrt {4{a^2} - 4a + 1} + 3a \cr & = \sqrt {{{\left( 1 \right)}^2} + {{\left( {2a} \right)}^2} - 2 \times 1 \times 2a} + 3a \cr & = \sqrt {{{\left( {1 - 2a} \right)}^2}} + 3a \cr & = \left( {1 - 2a} \right) + 3a \cr & = \left( {1 + a} \right) \cr & = \left( {1 + 0.1039} \right) \cr & = 1.1039 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: