5–√=2.236,5=2.236,\sqrt 5 = 2.236, then the value of 52" role="presentation">5–√252\frac{{\sqrt 5 }}{2} −" role="presentation">−− - 105" role="presentation">105–√105\frac{{10}}{{\sqrt 5 }} +" role="presentation">++ + 125" role="presentation">125−−−√125\sqrt {125} is equal to :" /> 5–√=2.236,5=2.236,\sqrt 5 = 2.236, then the value of 52" role="presentation">5–√252\frac{{\sqrt 5 }}{2} −" role="presentation">−− - 105" role="presentation">105–√105\frac{{10}}{{\sqrt 5 }} +" role="presentation">++ + 125" role="presentation">125−−−√125\sqrt {125} is equal to :" /> 5–√=2.236,5=2.236,\sqrt 5 = 2.236, then the value of 52" role="presentation">5–√252\frac{{\sqrt 5 }}{2} −" role="presentation">−− - 105" role="presentation">105–√105\frac{{10}}{{\sqrt 5 }} +" role="presentation">++ + 125" role="presentation">125−−−√125\sqrt {125} is equal to :" />

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If $\sqrt{5} = 2.236,$ $\sqrt 5 = 2.236,$ then the value of $\frac{\sqrt{5}}{2}$ $\frac{{\sqrt 5 }}{2}$ $-$ $-$ $\frac{10}{\sqrt{5}}$ $\frac{{10}}{{\sqrt 5 }}$ $+$ $+$ $\sqrt{125}$ $\sqrt {125}$ is equal to :

15.59
27.826
38.944
410.062

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \frac{\sqrt{5}}{2} - \frac{10}{\sqrt{5}} + \sqrt{125} \\ = \frac{{(\sqrt{5})}^{2} - 20 + 2 \sqrt{5} \times 5 \sqrt{5}}{2 \sqrt{5}} \\ = \frac{5 - 20 + 50}{2 \sqrt{5}} \\ = \frac{35}{2 \sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} \\ = \frac{35 \sqrt{5}}{10} \\ = \frac{7 \times 2.236}{2} \\ = 7 \times 1.118 \\ = 7.826 \end{aligned}

$\eqalign{ & \frac{{\sqrt 5 }}{2} - \frac{{10}}{{\sqrt 5 }} + \sqrt {125} \, \cr & = \frac{{{{\left( {\sqrt 5 } \right)}^2} - 20 + 2\sqrt 5 \times 5\sqrt 5 }}{{2\sqrt 5 }} \cr & = \frac{{5 - 20 + 50}}{{2\sqrt 5 }} \cr & = \frac{{35}}{{2\sqrt 5 }} \times \frac{{\sqrt 5 }}{{\sqrt 5 }} \cr & = \frac{{35\sqrt 5 }}{{10}} \cr & = \frac{{7 \times 2.236}}{2} \cr & = 7 \times 1.118 \cr & = 7.826 \cr}$

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then the value of

\frac{\sqrt{5}}{2}

$\frac{{\sqrt 5 }}{2}$

-

$-$

\frac{10}{\sqrt{5}}

$\frac{{10}}{{\sqrt 5 }}$

+

$+$

\sqrt{125}

$\sqrt {125}$ is equal to :", "text": "If

\sqrt{5} = 2.236,

$\sqrt 5 = 2.236,$ then the value of

\frac{\sqrt{5}}{2}

$\frac{{\sqrt 5 }}{2}$

-

$-$

\frac{10}{\sqrt{5}}

$\frac{{10}}{{\sqrt 5 }}$

+

$+$

\sqrt{125}

$\sqrt {125}$ is equal to :", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{\sqrt{5}}{2} - \frac{10}{\sqrt{5}} + \sqrt{125} \\ = \frac{{(\sqrt{5})}^{2} - 20 + 2 \sqrt{5} \times 5 \sqrt{5}}{2 \sqrt{5}} \\ = \frac{5 - 20 + 50}{2 \sqrt{5}} \\ = \frac{35}{2 \sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} \\ = \frac{35 \sqrt{5}}{10} \\ = \frac{7 \times 2.236}{2} \\ = 7 \times 1.118 \\ = 7.826 \end{aligned}

$\eqalign{ & \frac{{\sqrt 5 }}{2} - \frac{{10}}{{\sqrt 5 }} + \sqrt {125} \, \cr & = \frac{{{{\left( {\sqrt 5 } \right)}^2} - 20 + 2\sqrt 5 \times 5\sqrt 5 }}{{2\sqrt 5 }} \cr & = \frac{{5 - 20 + 50}}{{2\sqrt 5 }} \cr & = \frac{{35}}{{2\sqrt 5 }} \times \frac{{\sqrt 5 }}{{\sqrt 5 }} \cr & = \frac{{35\sqrt 5 }}{{10}} \cr & = \frac{{7 \times 2.236}}{2} \cr & = 7 \times 1.118 \cr & = 7.826 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{\sqrt{5}}{2} - \frac{10}{\sqrt{5}} + \sqrt{125} \\ = \frac{{(\sqrt{5})}^{2} - 20 + 2 \sqrt{5} \times 5 \sqrt{5}}{2 \sqrt{5}} \\ = \frac{5 - 20 + 50}{2 \sqrt{5}} \\ = \frac{35}{2 \sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} \\ = \frac{35 \sqrt{5}}{10} \\ = \frac{7 \times 2.236}{2} \\ = 7 \times 1.118 \\ = 7.826 \end{aligned}

$\eqalign{ & \frac{{\sqrt 5 }}{2} - \frac{{10}}{{\sqrt 5 }} + \sqrt {125} \, \cr & = \frac{{{{\left( {\sqrt 5 } \right)}^2} - 20 + 2\sqrt 5 \times 5\sqrt 5 }}{{2\sqrt 5 }} \cr & = \frac{{5 - 20 + 50}}{{2\sqrt 5 }} \cr & = \frac{{35}}{{2\sqrt 5 }} \times \frac{{\sqrt 5 }}{{\sqrt 5 }} \cr & = \frac{{35\sqrt 5 }}{{10}} \cr & = \frac{{7 \times 2.236}}{2} \cr & = 7 \times 1.118 \cr & = 7.826 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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