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A pump can fill a tank with water in 2 hours. Because of a leak, it took 2(¹/₃) hours to fill the tank. The leak can drain all the water of the tank in:

14(¹/₃) hours
27 hours
38 hours
414 hours

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Work done by the leak in 1 hour \\ = (\frac{1}{2} - \frac{3}{7}) = \frac{1}{14} \\ ∴ Leak will empty the tank in 14 hrs . \end{aligned}

$\eqalign{ & {\text{Work}}\,{\text{done}}\,{\text{by}}\,{\text{the}}\,{\text{leak}}\,{\text{in}}\,{\text{1}}\,{\text{hour}} \cr & = \left( {\frac{1}{2} - \frac{3}{7}} \right) = \frac{1}{{14}} \cr & \therefore {\text{Leak}}\,{\text{will}}\,{\text{empty}}\,{\text{the}}\,{\text{tank}}\,{\text{in}}\,{\text{14}}\,{\text{hrs}}. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Work done by the leak in 1 hour \\ = (\frac{1}{2} - \frac{3}{7}) = \frac{1}{14} \\ ∴ Leak will empty the tank in 14 hrs . \end{aligned}

$\eqalign{ & {\text{Work}}\,{\text{done}}\,{\text{by}}\,{\text{the}}\,{\text{leak}}\,{\text{in}}\,{\text{1}}\,{\text{hour}} \cr & = \left( {\frac{1}{2} - \frac{3}{7}} \right) = \frac{1}{{14}} \cr & \therefore {\text{Leak}}\,{\text{will}}\,{\text{empty}}\,{\text{the}}\,{\text{tank}}\,{\text{in}}\,{\text{14}}\,{\text{hrs}}. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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