log8–√log8log⁡8log⁡8{{\log \sqrt 8 } \over {\log 8}} is equal to:" /> log8–√log8log⁡8log⁡8{{\log \sqrt 8 } \over {\log 8}} is equal to:" /> log8–√log8log⁡8log⁡8{{\log \sqrt 8 } \over {\log 8}} is equal to:" />

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$\frac{\log \sqrt{8}}{\log 8}$ ${{\log \sqrt 8 } \over {\log 8}}$ is equal to:

1¹/₆
2¹/₄
3¹/₂
4¹/₈

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \frac{\log \sqrt{8}}{\log 8} = {\frac{\log (8)}{\log 8}}^{\frac{1}{2}} \\ = \frac{\frac{1}{2} \log 8}{\log 8} \\ = \frac{1}{2} \end{aligned}

$\eqalign{ & \frac{{\log \sqrt 8 }}{{\log 8}} = {\frac{{\log \left( 8 \right)}}{{\log 8}}^{\frac{1}{2}}} \cr & = \frac{{\frac{1}{2}\log 8}}{{\log 8}} \cr & = \frac{1}{2} \cr}$

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is equal to:", "text": "

\frac{\log \sqrt{8}}{\log 8}

${{\log \sqrt 8 } \over {\log 8}}$ is equal to:", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \frac{\log \sqrt{8}}{\log 8} = {\frac{\log (8)}{\log 8}}^{\frac{1}{2}} \\ = \frac{\frac{1}{2} \log 8}{\log 8} \\ = \frac{1}{2} \end{aligned}

$\eqalign{ & \frac{{\log \sqrt 8 }}{{\log 8}} = {\frac{{\log \left( 8 \right)}}{{\log 8}}^{\frac{1}{2}}} \cr & = \frac{{\frac{1}{2}\log 8}}{{\log 8}} \cr & = \frac{1}{2} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution: