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If log₁₀ 2 = 0.3010, the value of log₁₀ 80 is:

11.6020
21.9030
33.9030
4None of these

Answer:- 1

Explanation:-

Solution:

\begin{aligned} \log_{10} 80 \\ = \log_{10} (8 \times 10) \\ = \log_{10} 8 + \log_{10} 10 \\ = \log_{10} (2^{3}) + 1 \\ = 3 \log_{10} 2 + 1 \\ = (3 \times 0.3010) + 1 \\ 1.9030 \end{aligned}

$\eqalign{ & {\log _{10}}80 \cr & = {\log _{10}}\left( {8 \times 10} \right) \cr & = {\log _{10}}8 + {\log _{10}}10 \cr & = {\log _{10}}\left( {{2^3}} \right) + 1 \cr & = 3{\log _{10}}2 + 1 \cr & = \left( {3 \times 0.3010} \right) + 1 \cr & 1.9030 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} \log_{10} 80 \\ = \log_{10} (8 \times 10) \\ = \log_{10} 8 + \log_{10} 10 \\ = \log_{10} (2^{3}) + 1 \\ = 3 \log_{10} 2 + 1 \\ = (3 \times 0.3010) + 1 \\ 1.9030 \end{aligned}

$\eqalign{ & {\log _{10}}80 \cr & = {\log _{10}}\left( {8 \times 10} \right) \cr & = {\log _{10}}8 + {\log _{10}}10 \cr & = {\log _{10}}\left( {{2^3}} \right) + 1 \cr & = 3{\log _{10}}2 + 1 \cr & = \left( {3 \times 0.3010} \right) + 1 \cr & 1.9030 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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