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In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:

118 m
220 m
327 m
49 m

Answer:- 1

Explanation:-

Solution:

\begin{aligned} A : B = 100 : 90 \\ A : C = 100 : 72 \\ B : C = \frac{B}{A} \times \frac{A}{C} = \frac{90}{100} \times \frac{100}{72} = \frac{90}{72} \end{aligned}

$\eqalign{ & A:B = 100:90 \cr & A:C = 100:72 \cr & B:C = {B \over A} \times {A \over C} = {{90} \over {100}} \times {{100} \over {72}} = {{90} \over {72}} \cr}$ When B runs 90 m, C runs 72 m.
When B runs 100m, C run

(\frac{72}{90} \times 100) m = 80 m

$\left( {{{72} \over {90}} \times 100} \right)m = 80m$ ∴ B can give C 20m

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When B runs 90 m, C runs 72 m.
When B runs 100m, C run

(\frac{72}{90} \times 100) m = 80 m

$\left( {{{72} \over {90}} \times 100} \right)m = 80m$ ∴ B can give C 20m ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} A : B = 100 : 90 \\ A : C = 100 : 72 \\ B : C = \frac{B}{A} \times \frac{A}{C} = \frac{90}{100} \times \frac{100}{72} = \frac{90}{72} \end{aligned}

$\eqalign{ & A:B = 100:90 \cr & A:C = 100:72 \cr & B:C = {B \over A} \times {A \over C} = {{90} \over {100}} \times {{100} \over {72}} = {{90} \over {72}} \cr}$ When B runs 90 m, C runs 72 m.
When B runs 100m, C run

(\frac{72}{90} \times 100) m = 80 m

$\left( {{{72} \over {90}} \times 100} \right)m = 80m$ ∴ B can give C 20m ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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