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In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:

18 points
210 points
314 points
440 points

Answer:- 1

Explanation:-

Solution:

\begin{aligned} A : B = 100 : 80 \\ A : C = 100 : 72 \\ ∴ \frac{B}{C} = (\frac{B}{A} \times \frac{A}{C}) = (\frac{80}{100} \times \frac{100}{72}) \\ = \frac{10}{9} = \frac{100}{90} = 100 : 90 \\ ∴ B can give C 10 points \end{aligned}

$\eqalign{ & A:B = 100:80 \cr & A:C = 100:72 \cr & \therefore \frac{B}{C} = \left( {\frac{B}{A} \times \frac{A}{C}} \right) = \left( {\frac{{80}}{{100}} \times \frac{{100}}{{72}}} \right) \cr & = \frac{{10}}{9} = \frac{{100}}{{90}} = 100:90 \cr & \therefore {\text{B}}\,{\text{can}}\,{\text{give}}\,{\text{C}}\,{\text{10}}\,{\text{points}} \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} A : B = 100 : 80 \\ A : C = 100 : 72 \\ ∴ \frac{B}{C} = (\frac{B}{A} \times \frac{A}{C}) = (\frac{80}{100} \times \frac{100}{72}) \\ = \frac{10}{9} = \frac{100}{90} = 100 : 90 \\ ∴ B can give C 10 points \end{aligned}

$\eqalign{ & A:B = 100:80 \cr & A:C = 100:72 \cr & \therefore \frac{B}{C} = \left( {\frac{B}{A} \times \frac{A}{C}} \right) = \left( {\frac{{80}}{{100}} \times \frac{{100}}{{72}}} \right) \cr & = \frac{{10}}{9} = \frac{{100}}{{90}} = 100:90 \cr & \therefore {\text{B}}\,{\text{can}}\,{\text{give}}\,{\text{C}}\,{\text{10}}\,{\text{points}} \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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