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Calendar

1.It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

**Answer:**Option** 1**

Solution:

On 31Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.

∴ On 31

Thus, on 1

2.What was the day of the week on 28^{th} May, 2006?

**Answer:**Option** 1**

Solution:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) ≡ 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28 ) = 148 days

∴ 148 days = (21 weeks + 1 day) ≡ 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.

Given day is Sunday.

3.What was the day of the week on 17^{th} June, 1998?

**Answer:**Option** 1**

Solution:

17Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) ≡ 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan. Feb. March April May June

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

Therefore 168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

4.Today is Monday. After 61 days, it will be:

**Answer:**Option** 1**

Solution:

Each day of the week is repeated after 7 days.So, after 63 days, it will be Monday.

∴ After 61 days, it will be Saturday.

5.**If 6**^{th} March, 2005 is Monday, what was the day of the week on 6^{th} March, 2004?

**Answer:**Option** 1**

Solution:

The year 2004 is a leap year. So, it has 2 odd days.But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.

∴ The day on 6

Given that, 6

∴ 6

6.On what dates of April, 2001 did Wednesday fall?

**Answer:**Option** 1**

Solution:

We shall find the day on 11

Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April

(31 + 28 + 31 + 1) = 91 days ≡ 0 odd days.

Total number of odd days = (0 + 0 + 0) = 0

On 1

In April, 2001 Wednesday falls on 4

7.How many days are there in *x* weeks *x* days?

**Answer:**Option** 1**

Solution:

8.On 8^{th} Feb, 2005 it was Tuesday. What was the day of the week on 8^{th} Feb, 2004?

**Answer:**Option** 1**

Solution:

The year 2004 is a leap year. It has 2 odd days.∴ The day on 8

Hence, this day is Sunday.

9.The calendar for the year 2007 will be the same for the year:

**Answer:**Option** 1**

Solution:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.Sum = 14 odd days ≡ 0 odd days.

∴ Calendar for the year 2018 will be the same as for the year 2007.

10.Which of the following is not a leap year?

**Answer:**Option** 1**

Solution:

The century divisible by 400 is a leap year.∴ The year 700 is not a leap year.