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The average of the first five multiples of 9 is:

120
227
328
430

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Required average \\ = (\frac{total sum of multiple of 9}{5}) \\ = (\frac{9 + 18 + 27 + 36 + 45}{5}) \\ = 27 \end{aligned}

$\eqalign{ & {\text{Required}}\,{\text{average}} \cr & = \left( {\frac{{{\text{total}}\,{\text{sum}}\,{\text{of}}\,{\text{multiple}}\,{\text{of}}\,9}}{5}} \right) \cr & = \left( {\frac{{9 + 18 + 27 + 36 + 45}}{5}} \right) \cr & = 27 \cr}$
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27.

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Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27. ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Required average \\ = (\frac{total sum of multiple of 9}{5}) \\ = (\frac{9 + 18 + 27 + 36 + 45}{5}) \\ = 27 \end{aligned}

$\eqalign{ & {\text{Required}}\,{\text{average}} \cr & = \left( {\frac{{{\text{total}}\,{\text{sum}}\,{\text{of}}\,{\text{multiple}}\,{\text{of}}\,9}}{5}} \right) \cr & = \left( {\frac{{9 + 18 + 27 + 36 + 45}}{5}} \right) \cr & = 27 \cr}$
Note that, average of 9 and 45 is also 27.
And average of 18 and 36 is also 27. ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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