A heap of pebbles when made up into group of 32, 40, 72, leaves the remainder 10, 18 and 50 respectively. Find least number of pebbles in the heaps.

Explanation:-

In this type of problem we find the difference of divisors and their remainders.
Here difference,
32-10 = 22;
40-18 = 22;
72-50 = 22;
Here, in each case difference is same i.e. 22.
Then required number of pebbles is given by
[(LCM of 32, 40,72)-22];

32 = 2*2*2*2*2;

40 = 2*2*2*5;

72 = 2*2*2*3*3;
Hence,
LCM = 2*2*2*2*2*3*3*5 = 1440;
Thus,
Required number of pebbles,
= 1440-22 = 1418.