The HCF of two numbers, each having three digits, is 17 and their LCM is 714. The sum of the numbers will be:

  • 1289
  • 2391
  • 3221
  • 4731
Answer:- 1
Explanation:-

Solution:
Let the numbers be 17x and 17y where x and y are co-prime.
LCM = 17xy.
Now, 17xy = 714;
Or, xy = 42 = 6*7;
→x = 6 and y = 7;
Or, x = 7 and y = 6;
1st number = 17*6 = 102;
2nd number = 17*7 = 221;
Sum = 102+119 = 221.

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