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The HCF of 2472, 1284 and a third number 'N' is 12. If their LCM is 2³3²5103107, then the number 'N' is:

Answer:- 1

Explanation:-

Solution:

We have,
HCF of the numbers * LCM of the numbers = Multiplication of the numbers.
(12)*(2³*3²*5*103*107) = 2472* 1284*N;
Hence,
N =

\frac{{(12) \times (2^{3} \times 3^{2} \times 5 \times 103 \times 107)}}{2472 \times 1284}

$\frac{{\{ \left( {12} \right) \times \left( {{2^3} \times {3^2} \times 5 \times 103 \times 107} \right)\} }}{{2472 \times 1284}}$
Or, N = 3*5.

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Or, N = 3*5.

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

We have,
HCF of the numbers * LCM of the numbers = Multiplication of the numbers.
(12)*(2³*3²*5*103*107) = 2472* 1284*N;
Hence,
N =

\frac{{(12) \times (2^{3} \times 3^{2} \times 5 \times 103 \times 107)}}{2472 \times 1284}

$\frac{{\{ \left( {12} \right) \times \left( {{2^3} \times {3^2} \times 5 \times 103 \times 107} \right)\} }}{{2472 \times 1284}}$
Or, N = 3*5.

", "dateCreated": "7/24/2019 10:09:12 AM" } }

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