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If a = 2.361, b = 3.263, and c = 5.624, then the value of a³ + b³ - c³ + 3abc is?

1(p- q)(q - r)³ + (r - p)³
23(p - q)(q - r)(r - p)
30
41

Answer:- 1

Explanation:-

Solution:

\begin{aligned} a = 2.361 \\ b = 3.263 \\ c = 5.624 \\ a + b - c = 0 \\ 2.361 + 3.263 - 5.624 = 0 \\ 0 = 0 \\ ∴ a^{3} + b^{3} - c^{3} + 3 a b c \\ \Rightarrow 0 \end{aligned}

$\eqalign{ & a = 2.361 \cr & b = 3.263 \cr & c = 5.624 \cr & a + b - c = 0 \cr & 2.361 + 3.263 - 5.624 = 0 \cr & 0 = 0 \cr & \therefore {a^3} + {b^3} - {c^3} + 3abc \cr & \Rightarrow 0 \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} a = 2.361 \\ b = 3.263 \\ c = 5.624 \\ a + b - c = 0 \\ 2.361 + 3.263 - 5.624 = 0 \\ 0 = 0 \\ ∴ a^{3} + b^{3} - c^{3} + 3 a b c \\ \Rightarrow 0 \end{aligned}

$\eqalign{ & a = 2.361 \cr & b = 3.263 \cr & c = 5.624 \cr & a + b - c = 0 \cr & 2.361 + 3.263 - 5.624 = 0 \cr & 0 = 0 \cr & \therefore {a^3} + {b^3} - {c^3} + 3abc \cr & \Rightarrow 0 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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