(2.644)2−(2.356)20.288=?(2.644)2−(2.356)20.288=?\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} = ?" /> (2.644)2−(2.356)20.288=?(2.644)2−(2.356)20.288=?\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} = ?" /> (2.644)2−(2.356)20.288=?(2.644)2−(2.356)20.288=?\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} = ?" />

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Simplification of $\frac{{(2.644)}^{2} - {(2.356)}^{2}}{0.288} = ?$ $\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} = ?$

16.91
27
36.81
47.1

Answer:- 1

Explanation:-

Solution:

\begin{aligned} According to the question \\ \frac{{(2.644)}^{2} - {(2.356)}^{2}}{0.288} \\ [∵ a^{2} - b^{2} = (a + b) (a - b)] \\ \Rightarrow \frac{(3.4567 + 3.4533) (3.4567 - 3.4533)}{0.0034} \\ \Rightarrow \frac{6.91 \times 0.0034}{0.0034} \\ \Rightarrow 6.91 \end{aligned}

$\eqalign{ & {\text{According to the question}} \cr & {\text{ }}\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} \cr & \left[ {\because {a^2} - {b^2} = \left( {a + b} \right)\left( {a - b} \right)} \right] \cr & \Rightarrow \frac{{\left( {3.4567 + 3.4533} \right)\left( {3.4567 - 3.4533} \right)}}{{0.0034}} \cr & \Rightarrow \frac{{6.91 \times 0.0034}}{{0.0034}} \cr & \Rightarrow 6.91 \cr}$

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", "text": "Simplification of

\frac{{(2.644)}^{2} - {(2.356)}^{2}}{0.288} = ?

$\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} = ?$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to the question \\ \frac{{(2.644)}^{2} - {(2.356)}^{2}}{0.288} \\ [∵ a^{2} - b^{2} = (a + b) (a - b)] \\ \Rightarrow \frac{(3.4567 + 3.4533) (3.4567 - 3.4533)}{0.0034} \\ \Rightarrow \frac{6.91 \times 0.0034}{0.0034} \\ \Rightarrow 6.91 \end{aligned}

$\eqalign{ & {\text{According to the question}} \cr & {\text{ }}\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} \cr & \left[ {\because {a^2} - {b^2} = \left( {a + b} \right)\left( {a - b} \right)} \right] \cr & \Rightarrow \frac{{\left( {3.4567 + 3.4533} \right)\left( {3.4567 - 3.4533} \right)}}{{0.0034}} \cr & \Rightarrow \frac{{6.91 \times 0.0034}}{{0.0034}} \cr & \Rightarrow 6.91 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} According to the question \\ \frac{{(2.644)}^{2} - {(2.356)}^{2}}{0.288} \\ [∵ a^{2} - b^{2} = (a + b) (a - b)] \\ \Rightarrow \frac{(3.4567 + 3.4533) (3.4567 - 3.4533)}{0.0034} \\ \Rightarrow \frac{6.91 \times 0.0034}{0.0034} \\ \Rightarrow 6.91 \end{aligned}

$\eqalign{ & {\text{According to the question}} \cr & {\text{ }}\frac{{{{\left( {2.644} \right)}^2} - {{\left( {2.356} \right)}^2}}}{{0.288}} \cr & \left[ {\because {a^2} - {b^2} = \left( {a + b} \right)\left( {a - b} \right)} \right] \cr & \Rightarrow \frac{{\left( {3.4567 + 3.4533} \right)\left( {3.4567 - 3.4533} \right)}}{{0.0034}} \cr & \Rightarrow \frac{{6.91 \times 0.0034}}{{0.0034}} \cr & \Rightarrow 6.91 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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