(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2−−−−−−−−−−−−−−−−−−−−−−−−−⎷(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}} " /> (0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2−−−−−−−−−−−−−−−−−−−−−−−−−⎷(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}} " /> (0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2−−−−−−−−−−−−−−−−−−−−−−−−−⎷(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}} " />

(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2

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Answer:- 1
Explanation:-

Solution:
According to the question,(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2=0.0009+0.0441+0.0042250.000009+0.000441+0.00004225=0.0492250.00049225=100=10

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", "text": "
(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
According to the question,(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2=0.0009+0.0441+0.0042250.000009+0.000441+0.00004225=0.0492250.00049225=100=10
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
According to the question,(0.03)2+(0.21)2+(0.065)2(0.003)2+(0.021)2+(0.0065)2=0.0009+0.0441+0.0042250.000009+0.000441+0.00004225=0.0492250.00049225=100=10
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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