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# Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

Option :

Explanation:

Solution:
$\begin{array}{rl}& \text{Let}\phantom{\rule{thinmathspace}{0ex}}\text{the}\phantom{\rule{thinmathspace}{0ex}}\text{number}\phantom{\rule{thinmathspace}{0ex}}\text{be}\phantom{\rule{thinmathspace}{0ex}}x\\ & \text{Then},\phantom{\rule{thinmathspace}{0ex}}x+17=\frac{60}{x}\\ & ⇒{x}^{2}+17x-60=0\\ & ⇒\left(x+20\right)\left(x-3\right)=0\\ & ⇒x=3\end{array}$