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In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

Option :

Answer:Option 1

Explanation:

Solution:
Totalnumberofballs=(8+7+6)=21.LetE = eventthattheballdrawnis neitherrednorgreen = eventthattheballdrawnisblue.n(E)=7.P(E)=n(E)n(S)=721=13



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