Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8 runs. His new average is:

  • 120
  • 221
  • 328
  • 432
Answer:- 1
Explanation:-

Solution:
Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x+8)*10 runs in 10 innings.
Now,
9x+100=10×(x+8)or,9x+100=10x+80or,x=10080or,x=20Newaverage=(x+8)=28runs

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x+8)*10 runs in 10 innings.
Now,
9x+100=10×(x+8)or,9x+100=10x+80or,x=10080or,x=20Newaverage=(x+8)=28runs
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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