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The average age of A, B, C, D and E is 40 years. The average age of A and B is 35 years and the average of C and D is 42 years. Age of E is :

148
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445

Answer:- 1

Explanation:-

Solution:

\begin{aligned} A + B + C + D + E = 40 \times 5 = 200 \\ A + B = 35 \times 2 = 70 \\ C + D = 42 \times 2 = 84 \\ Therefore, \\ E = (A + B + C + D + E) - (A + B + C + D) \\ = 200 - 70 - 84 \\ = 46 y e a r s \end{aligned}

$\eqalign{ & A + B + C + D + E = 40 \times 5 = 200 \cr & A + B = 35 \times 2 = 70 \cr & C + D = 42 \times 2 = 84 \cr & {\text{Therefore}}, \cr & E = \left( {A + B + C + D + E} \right) - \left( {A + B + C + D} \right) \cr & \,\,\,\,\,\,\, = 200 - 70 - 84 \cr & \,\,\,\,\,\,\, = 46\,years \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} A + B + C + D + E = 40 \times 5 = 200 \\ A + B = 35 \times 2 = 70 \\ C + D = 42 \times 2 = 84 \\ Therefore, \\ E = (A + B + C + D + E) - (A + B + C + D) \\ = 200 - 70 - 84 \\ = 46 y e a r s \end{aligned}

$\eqalign{ & A + B + C + D + E = 40 \times 5 = 200 \cr & A + B = 35 \times 2 = 70 \cr & C + D = 42 \times 2 = 84 \cr & {\text{Therefore}}, \cr & E = \left( {A + B + C + D + E} \right) - \left( {A + B + C + D} \right) \cr & \,\,\,\,\,\,\, = 200 - 70 - 84 \cr & \,\,\,\,\,\,\, = 46\,years \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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