Explanation:-
Solution:
Let a, b, c, d, and e be the five positive numbers in the decreasing order of size such that e is the
smallest number. We are given that the average of the five numbers is 25. Hence, we have the equation
(a+b+c+d+e)/5=25
a+b+c+d+e =125 ----------- (1) by multiplying by 5.
The smallest number in a set is at least less than the average of the numbers in the set if at least one number is different.
For example, the average of 1, 2, and 3 is 2, and the smallest number in the set 1 is less than the
average 2. Hence, we have the inequality
0 < e<25.
0> - e> - 25 by multiplying both sides of the inequality by -1 and flipping the directions of the inequalities.
Adding this inequality to equation (1) yields
0+125>(a+b+c+d+e)+(-e)>125 - 25
125>(a+b+c+d)>100
125>(a+b+c+d+0)>100 by adding by 0
25>(a+b
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