1414\frac{1}{4} p.a for 2 years. Find his gain in the transaction per year. " /> 1414\frac{1}{4} p.a for 2 years. Find his gain in the transaction per year. " /> 1414\frac{1}{4} p.a for 2 years. Find his gain in the transaction per year. " />

A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6
14
p.a for 2 years. Find his gain in the transaction per year.

  • 1Rs. 112.50
  • 2Rs. 125
  • 3Rs. 150
  • 4Rs. 167.50
Answer:- 1
Explanation:-

Solution:
Gainin2years=Rs.[(5000×254×2100)(5000×4×2100)]=Rs.(625400)=Rs.225.Gainin1year=Rs.(2252)=Rs.112.50

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p.a for 2 years. Find his gain in the transaction per year. ", "text": "A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6
14
p.a for 2 years. Find his gain in the transaction per year. ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
Gainin2years=Rs.[(5000×254×2100)(5000×4×2100)]=Rs.(625400)=Rs.225.Gainin1year=Rs.(2252)=Rs.112.50
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Gainin2years=Rs.[(5000×254×2100)(5000×4×2100)]=Rs.(625400)=Rs.225.Gainin1year=Rs.(2252)=Rs.112.50
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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