4949\frac{4}{9} of the principal and the number of years is equal to the rate percent per annum. The rate per annum is = ?" /> 4949\frac{4}{9} of the principal and the number of years is equal to the rate percent per annum. The rate per annum is = ?" /> 4949\frac{4}{9} of the principal and the number of years is equal to the rate percent per annum. The rate per annum is = ?" />

The simple interest on a sum of money is
49
of the principal and the number of years is equal to the rate percent per annum. The rate per annum is = ?

  • 15%
  • 2
    623
    %
  • 36%
  • 4
    715
    %
Answer:- 1
Explanation:-

Solution:
Let the principal = 9 units Hence simple interest = 49×9 = 4 unitsLet,Rate of interest = R% R = T (given)By using formulaSI = P×T×R1004=9×R×R100R2=4009R = 203=623%

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of the principal and the number of years is equal to the rate percent per annum. The rate per annum is = ?", "text": "The simple interest on a sum of money is
49
of the principal and the number of years is equal to the rate percent per annum. The rate per annum is = ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "
Solution:
Let the principal = 9 units Hence simple interest = 49×9 = 4 unitsLet,Rate of interest = R% R = T (given)By using formulaSI = P×T×R1004=9×R×R100R2=4009R = 203=623%
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Let the principal = 9 units Hence simple interest = 49×9 = 4 unitsLet,Rate of interest = R% R = T (given)By using formulaSI = P×T×R1004=9×R×R100R2=4009R = 203=623%
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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