6146146\frac{1}{4} % p.a. for 2 years. Find his gain in the transaction per year." /> 6146146\frac{1}{4} % p.a. for 2 years. Find his gain in the transaction per year." /> 6146146\frac{1}{4} % p.a. for 2 years. Find his gain in the transaction per year." />

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A person borrows Rs. 5000 for 2 year at 4% p.a. simple interest. He immediately lends it to another person at $6 \frac{1}{4}$ $6\frac{1}{4}$ % p.a. for 2 years. Find his gain in the transaction per year.

1Rs. 112.50
2Rs. 125
3Rs. 150
4Rs. 167.50

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Gain in 2 years \\ = [(5000 \times \frac{25}{4} \times \frac{2}{100}) - (\frac{5000 \times 4 \times 2}{100})] \\ = Rs . (625 - 400) \\ = Rs . 225. \\ ∴ Gain 1 year = Rs . (\frac{225}{2}) \\ = Rs . 112.50 \end{aligned}

$\eqalign{ & {\text{Gain in 2 years}} \cr & = \left[ {\left( {5000 \times \frac{{25}}{4} \times \frac{2}{{100}}} \right) - \left( {\frac{{5000 \times 4 \times 2}}{{100}}} \right)} \right] \cr & = {\text{Rs}}{\text{.}}\left( {625 - 400} \right) \cr & = {\text{Rs}}{\text{. }}225. \cr & \therefore {\text{Gain 1 year}} = {\text{Rs}}{\text{.}}\left( {\frac{{225}}{2}} \right) \cr & = {\text{Rs}}{\text{. }}112.50 \cr}$

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% p.a. for 2 years. Find his gain in the transaction per year.", "text": "A person borrows Rs. 5000 for 2 year at 4% p.a. simple interest. He immediately lends it to another person at

6 \frac{1}{4}

$6\frac{1}{4}$ % p.a. for 2 years. Find his gain in the transaction per year.", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Gain in 2 years \\ = [(5000 \times \frac{25}{4} \times \frac{2}{100}) - (\frac{5000 \times 4 \times 2}{100})] \\ = Rs . (625 - 400) \\ = Rs . 225. \\ ∴ Gain 1 year = Rs . (\frac{225}{2}) \\ = Rs . 112.50 \end{aligned}

$\eqalign{ & {\text{Gain in 2 years}} \cr & = \left[ {\left( {5000 \times \frac{{25}}{4} \times \frac{2}{{100}}} \right) - \left( {\frac{{5000 \times 4 \times 2}}{{100}}} \right)} \right] \cr & = {\text{Rs}}{\text{.}}\left( {625 - 400} \right) \cr & = {\text{Rs}}{\text{. }}225. \cr & \therefore {\text{Gain 1 year}} = {\text{Rs}}{\text{.}}\left( {\frac{{225}}{2}} \right) \cr & = {\text{Rs}}{\text{. }}112.50 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Gain in 2 years \\ = [(5000 \times \frac{25}{4} \times \frac{2}{100}) - (\frac{5000 \times 4 \times 2}{100})] \\ = Rs . (625 - 400) \\ = Rs . 225. \\ ∴ Gain 1 year = Rs . (\frac{225}{2}) \\ = Rs . 112.50 \end{aligned}

$\eqalign{ & {\text{Gain in 2 years}} \cr & = \left[ {\left( {5000 \times \frac{{25}}{4} \times \frac{2}{{100}}} \right) - \left( {\frac{{5000 \times 4 \times 2}}{{100}}} \right)} \right] \cr & = {\text{Rs}}{\text{.}}\left( {625 - 400} \right) \cr & = {\text{Rs}}{\text{. }}225. \cr & \therefore {\text{Gain 1 year}} = {\text{Rs}}{\text{.}}\left( {\frac{{225}}{2}} \right) \cr & = {\text{Rs}}{\text{. }}112.50 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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