India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

Deepak invested an amount of Rs. 21250 for 6 years. At what rate of simple interest will be obtain the total amount of Rs. 26350 at the end of 6 years?

15 p.c.p.a
26 p.c.p.a
38 p.c.p.a
4None of these

Answer:- 1

Explanation:-

Solution:

\begin{aligned} P = Rs . 21250 \\ S .I . \\ = Rs . (26350 - 21250) \\ = Rs . 5100 \\ T = 6 years . \\ ∴ Rate = (\frac{100 \times 5100}{21250 \times 6}) % \\ = 4 % \end{aligned}

$\eqalign{ & {\text{P}} = {\text{Rs}}{\text{. 21250}} \cr & {\text{S}}{\text{.I}}{\text{.}} \cr & = {\text{Rs}}{\text{. }}\left( {{\text{26350}} - {\text{21250}}} \right) \cr & = {\text{Rs}}{\text{. }}5100 \cr & {\text{T}} = {\text{6 years}}{\text{.}} \cr & \therefore {\text{Rate}} = \left( {\frac{{100 \times 5100}}{{{\text{21250}} \times {\text{6}}}}} \right)\% \cr & = 4\% \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} P = Rs . 21250 \\ S .I . \\ = Rs . (26350 - 21250) \\ = Rs . 5100 \\ T = 6 years . \\ ∴ Rate = (\frac{100 \times 5100}{21250 \times 6}) % \\ = 4 % \end{aligned}

$\eqalign{ & {\text{P}} = {\text{Rs}}{\text{. 21250}} \cr & {\text{S}}{\text{.I}}{\text{.}} \cr & = {\text{Rs}}{\text{. }}\left( {{\text{26350}} - {\text{21250}}} \right) \cr & = {\text{Rs}}{\text{. }}5100 \cr & {\text{T}} = {\text{6 years}}{\text{.}} \cr & \therefore {\text{Rate}} = \left( {\frac{{100 \times 5100}}{{{\text{21250}} \times {\text{6}}}}} \right)\% \cr & = 4\% \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book