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At what rate of simple interest per annum can an amount of Rs. 1553.40 be obtained on the principal amount of Rs. 8630 after 3 years?

14 p.c.p.a
25 p.c.p.a
37 p.c.p.a
4None of these

Answer:- 1

Explanation:-

Solution:

\begin{aligned} P = Rs .8630 \\ S .I . = Rs .1553 .40 \\ T = 3 years . \\ ∴ Rate \\ = (\frac{100 \times 1553.40}{8630 \times 3}) % \\ = 6 % . \end{aligned}

$\eqalign{ & {\text{P}} = {\text{Rs}}{\text{.8630}} \cr & {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{.1553}}{\text{.40}} \cr & {\text{T}} = {\text{3 years}}. \cr & \therefore {\text{Rate}} \cr & = \left( {\frac{{100 \times 1553.40}}{{8630 \times 3}}} \right)\% \cr & = 6\% . \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} P = Rs .8630 \\ S .I . = Rs .1553 .40 \\ T = 3 years . \\ ∴ Rate \\ = (\frac{100 \times 1553.40}{8630 \times 3}) % \\ = 6 % . \end{aligned}

$\eqalign{ & {\text{P}} = {\text{Rs}}{\text{.8630}} \cr & {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{.1553}}{\text{.40}} \cr & {\text{T}} = {\text{3 years}}. \cr & \therefore {\text{Rate}} \cr & = \left( {\frac{{100 \times 1553.40}}{{8630 \times 3}}} \right)\% \cr & = 6\% . \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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