A certain sum of money becomes three times of itself in 20 years at simple interest. In how many years does it become double itself at the same rate of simple interest ?

  • 18 years
  • 210 years
  • 312 years
  • 414 years
Answer:- 1
Explanation:-

Solution:
Let principal = Pamount = 3PInterest = 3PP = 2PAccording to the question,2P = P×R×20100R = 10% 

Let after t years it will become double
Hence,Interest = 2PP = PP = P×10×t100t = 10 years

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Let after t years it will become double
Hence,Interest = 2PP = PP = P×10×t100t = 10 years
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "
Solution:
Let principal = Pamount = 3PInterest = 3PP = 2PAccording to the question,2P = P×R×20100R = 10% 

Let after t years it will become double
Hence,Interest = 2PP = PP = P×10×t100t = 10 years
", "dateCreated": "7/24/2019 10:09:12 AM" } }
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