In how many years will a sum of money double itself at 18.75% per annum simple interest?

14 years 5 months
25 years 4 months
36 years 2 months
46 year 5 months

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Let sum  =  Rs . x . \\ Then, \\ S .I .  =  Rs . x . \\ ∴ T i m e = (\frac{100 \times S .I .}{P \times R}) \\ = (\frac{100 \times x}{x \times 18.75}) years \\ = \frac{26}{3} years \\ = 5 \frac{1}{3} years \\ = 5 years 4 months . \end{aligned}

$\eqalign{ & {\text{Let sum = Rs}}{\text{. }}x{\text{.}} \cr & {\text{Then,}} \cr & {\text{S}}{\text{.I}}{\text{. = Rs}}{\text{. }}x{\text{.}} \cr & \therefore Time = \left( {\frac{{100 \times {\text{S}}{\text{.I}}{\text{.}}}}{{{\text{P}} \times {\text{R}}}}} \right) \cr & = \left( {\frac{{100 \times x}}{{x \times 18.75}}} \right){\text{years}} \cr & = \frac{{26}}{3}{\text{years}} \cr & = 5\frac{1}{3}{\text{years}} \cr & = {\text{5 years 4 months}}{\text{.}} \cr}$