1623162316\frac{2}{3} % per annum ?" /> 1623162316\frac{2}{3} % per annum ?" /> 1623162316\frac{2}{3} % per annum ?" />

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In how many years will the simple interest on a sum of money be equal to the principal at the rate of $16 \frac{2}{3}$ $16\frac{2}{3}$ % per annum ?

14 years
25 years
36 years
48 years

Answer:- 1

Explanation:-

Solution:

\begin{aligned} 16 \frac{2}{3} = \frac{1 \to Interest}{6 \to Principal} \\ Let principal  =  6 \\ Interest  =  6 \\ Time  =  t years \\ By using formula \\ 6 = \frac{6 \times 50 \times t}{3 \times 100} \\ \Rightarrow t = 6 years \end{aligned}

$\eqalign{ & {\text{16}}\frac{2}{3} = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr & {\text{Let principal = 6}} \cr & {\text{Interest = 6}} \cr & {\text{Time = t years}} \cr & {\text{By using formula }} \cr & {\text{6}} = \frac{{6 \times 50 \times {\text{t}}}}{{3 \times 100}} \cr & \Rightarrow {\text{t}} = 6\,{\text{years}} \cr}$ Alternate
Note : In such type of questions to save your valuable time think like the given way.

\begin{aligned} Rate % \\ =  16 \frac{2}{3} % = \frac{1 \to Interest}{6 \to Principal} \\ Represent for 1 years \\ According to the question, \\ Principal  =  Interest \\ 6  =  1 \times 6 \\ Hence, \\ Time  =  1 \times 6 \\ =  6 years \end{aligned}

$\eqalign{ & {\text{Rate}}\% \cr & {\text{ = 16}}\frac{2}{3}\% = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr & {\text{Represent for 1 years}} \cr & {\text{According to the question,}} \cr & {\text{Principal = Interest}} \cr & {\text{6 = 1}} \times {\text{6}} \cr & {\text{Hence,}} \cr & {\text{Time = 1}} \times {\text{6}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 6 years}} \cr}$
Note : If interest will be six times then time will also be six times.

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% per annum ?", "text": "In how many years will the simple interest on a sum of money be equal to the principal at the rate of

16 \frac{2}{3}

$16\frac{2}{3}$ % per annum ?", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" }, "answerCount": "4", "acceptedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 16 \frac{2}{3} = \frac{1 \to Interest}{6 \to Principal} \\ Let principal  =  6 \\ Interest  =  6 \\ Time  =  t years \\ By using formula \\ 6 = \frac{6 \times 50 \times t}{3 \times 100} \\ \Rightarrow t = 6 years \end{aligned}

$\eqalign{ & {\text{16}}\frac{2}{3} = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr & {\text{Let principal = 6}} \cr & {\text{Interest = 6}} \cr & {\text{Time = t years}} \cr & {\text{By using formula }} \cr & {\text{6}} = \frac{{6 \times 50 \times {\text{t}}}}{{3 \times 100}} \cr & \Rightarrow {\text{t}} = 6\,{\text{years}} \cr}$ Alternate
Note : In such type of questions to save your valuable time think like the given way.

\begin{aligned} Rate % \\ =  16 \frac{2}{3} % = \frac{1 \to Interest}{6 \to Principal} \\ Represent for 1 years \\ According to the question, \\ Principal  =  Interest \\ 6  =  1 \times 6 \\ Hence, \\ Time  =  1 \times 6 \\ =  6 years \end{aligned}

$\eqalign{ & {\text{Rate}}\% \cr & {\text{ = 16}}\frac{2}{3}\% = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr & {\text{Represent for 1 years}} \cr & {\text{According to the question,}} \cr & {\text{Principal = Interest}} \cr & {\text{6 = 1}} \times {\text{6}} \cr & {\text{Hence,}} \cr & {\text{Time = 1}} \times {\text{6}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 6 years}} \cr}$
Note : If interest will be six times then time will also be six times. ", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} 16 \frac{2}{3} = \frac{1 \to Interest}{6 \to Principal} \\ Let principal  =  6 \\ Interest  =  6 \\ Time  =  t years \\ By using formula \\ 6 = \frac{6 \times 50 \times t}{3 \times 100} \\ \Rightarrow t = 6 years \end{aligned}

$\eqalign{ & {\text{16}}\frac{2}{3} = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr & {\text{Let principal = 6}} \cr & {\text{Interest = 6}} \cr & {\text{Time = t years}} \cr & {\text{By using formula }} \cr & {\text{6}} = \frac{{6 \times 50 \times {\text{t}}}}{{3 \times 100}} \cr & \Rightarrow {\text{t}} = 6\,{\text{years}} \cr}$ Alternate
Note : In such type of questions to save your valuable time think like the given way.

\begin{aligned} Rate % \\ =  16 \frac{2}{3} % = \frac{1 \to Interest}{6 \to Principal} \\ Represent for 1 years \\ According to the question, \\ Principal  =  Interest \\ 6  =  1 \times 6 \\ Hence, \\ Time  =  1 \times 6 \\ =  6 years \end{aligned}

$\eqalign{ & {\text{Rate}}\% \cr & {\text{ = 16}}\frac{2}{3}\% = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr & {\text{Represent for 1 years}} \cr & {\text{According to the question,}} \cr & {\text{Principal = Interest}} \cr & {\text{6 = 1}} \times {\text{6}} \cr & {\text{Hence,}} \cr & {\text{Time = 1}} \times {\text{6}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 6 years}} \cr}$
Note : If interest will be six times then time will also be six times. ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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