If a sum doubles in 6 years, how much will it be in 8 years ?

1 $1 \frac{1}{2}$ $1\frac{1}{2}$ times
2 $1 \frac{1}{3}$ $1\frac{1}{3}$ times
3 $1 \frac{1}{4}$ $1\frac{1}{4}$ times
4 $1 \frac{3}{4}$ $1\frac{3}{4}$ times

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Now, sum = Rs . x, \\ Time = 8 years \\ Rate = 6 \frac{1}{4} % \\ ∴ S .I . = Rs . (\frac{x \times 25 \times 8}{100 \times 4}) \\ = Rs . \frac{x}{2} \\ So, amount = \\ Rs . (x + \frac{x}{2}) \\ = Rs . \frac{3 x}{2} \\ = 1 \frac{1}{2} times \end{aligned}

$\eqalign{ & {\text{Now}}{\text{, sum}} = {\text{Rs}}{\text{. }}x, \cr & {\text{Time}} = 8\,{\text{years}} \cr & {\text{Rate}} = 6\frac{1}{4}\% \cr & \therefore {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{.}}\left( {\frac{{x \times 25 \times 8}}{{100 \times 4}}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\, = {\text{Rs}}{\text{. }}\frac{x}{2} \cr & {\text{So, amount}} = \cr & {\text{Rs}}{\text{.}}\left( {x + \frac{x}{2}} \right) \cr & = {\text{Rs}}{\text{. }}\frac{{3x}}{2} \cr & = 1\frac{1}{2}{\text{ times}} \cr}$