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A lends Rs. 2500 to B and a certain sum to C at the same time at 7% p.a. simple interest. If after 4 years, A altogether receives Rs. 1120 as interest from B and C, then the sum lent to C is :

1Rs. 700
2Rs. 1500
3Rs. 4000
4Rs. 6500

Answer:- 1

Explanation:-

Solution:

Let the sum lent to C be Rs. x.
Then,

\begin{aligned} (\frac{2500 \times 7 \times 4}{100}) + (\frac{x \times 7 \times 4}{100}) = 1120 \\ \Rightarrow \frac{7 x}{25} = (1120 - 700) \\ \Rightarrow x = (\frac{420 \times 25}{7}) \\ = 1500. \end{aligned}

$\eqalign{ & \left( {\frac{{2500 \times 7 \times 4}}{{100}}} \right) + \left( {\frac{{x \times 7 \times 4}}{{100}}} \right) = 1120 \cr & \Rightarrow \frac{{7x}}{{25}} = \left( {1120 - 700} \right) \cr & \Rightarrow x = \left( {\frac{{420 \times 25}}{7}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\, = 1500. \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the sum lent to C be Rs. x.
Then,

\begin{aligned} (\frac{2500 \times 7 \times 4}{100}) + (\frac{x \times 7 \times 4}{100}) = 1120 \\ \Rightarrow \frac{7 x}{25} = (1120 - 700) \\ \Rightarrow x = (\frac{420 \times 25}{7}) \\ = 1500. \end{aligned}

$\eqalign{ & \left( {\frac{{2500 \times 7 \times 4}}{{100}}} \right) + \left( {\frac{{x \times 7 \times 4}}{{100}}} \right) = 1120 \cr & \Rightarrow \frac{{7x}}{{25}} = \left( {1120 - 700} \right) \cr & \Rightarrow x = \left( {\frac{{420 \times 25}}{7}} \right) \cr & \,\,\,\,\,\,\,\,\,\,\,\, = 1500. \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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