Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then,
= 4x + 9y = 13400 ......(i)
and,
10% of 4x + 20% of 9y = 1880
⇒25x+95y=1880⇒2x+9y=9400....(ii)
Solving (i) and (ii), we get:
x = 2000 and y = 600
∴ Cost price of each horse = Rs. 2000
Solving (i) and (ii), we get:
x = 2000 and y = 600
∴ Cost price of each horse = Rs. 2000
",
"dateCreated": "7/24/2019 10:09:12 AM",
"author": {
"@type": "Person",
"name": "Nitin Sir"
}
},
"suggestedAnswer": {
"@type": "Answer",
"text": "
Solution:
Let C.P. of each horse be Rs. x and C.P. of each cow be Rs. y.
Then,
= 4x + 9y = 13400 ......(i)
and,
10% of 4x + 20% of 9y = 1880
⇒25x+95y=1880⇒2x+9y=9400....(ii)
Solving (i) and (ii), we get:
x = 2000 and y = 600
∴ Cost price of each horse = Rs. 2000
",
"dateCreated": "7/24/2019 10:09:12 AM"
}
}
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