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An article was sold for Rs. y after giving a discount of x%. Then, its list price is ?

1^100y/_{(100 - x)}
2^100y/_{(1 - x)}
3^100y/_{(10 - x)}
4None of these

Answer:- 4

Explanation:-

Solution:

Let the list price be Rs. z.

∴ (100 - x) % of z = y . \Rightarrow (100 - x 100) \times z = y . \Rightarrow z = (100 y 100 - x) .

$\eqalign{ & \therefore \left( {100 - x} \right)\% {\text{ of z}} = {\text{y}}. \cr & \Rightarrow \left( {\frac{{100 - x}}{{100}}} \right) \times {\text{z}} = {\text{y}}. \cr & \Rightarrow {\text{z}} = \left( {\frac{{100{\text{y}}}}{{100 - x}}} \right). \cr}$

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", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the list price be Rs. z.

∴ (100 - x) % of z = y . \Rightarrow (100 - x 100) \times z = y . \Rightarrow z = (100 y 100 - x) .

$\eqalign{ & \therefore \left( {100 - x} \right)\% {\text{ of z}} = {\text{y}}. \cr & \Rightarrow \left( {\frac{{100 - x}}{{100}}} \right) \times {\text{z}} = {\text{y}}. \cr & \Rightarrow {\text{z}} = \left( {\frac{{100{\text{y}}}}{{100 - x}}} \right). \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

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