How many pairs of natural numbers is there the difference of whose squares are 45.

  • 11
  • 22
  • 33
  • 44
Answer:- 1
Explanation:-

Solution:
(x2 - y2) = 45;
Or, (x - y)(x + y) = 45.
Thus, the factors of 45 possibles are 15, 3, 9, 5, 1 and 45.
Hence, numbers are 9 and 6 or 7 and 2 or 23 and 22.
So, number of such pairs = 3.

Post your Comments

Your comments will be displayed only after manual approval.

Test
Classes
E-Book