A man sells chocolates which are in the boxes. Only either full box or half a box of chocolates can be purchased from him. A customer comes and buys half the number of boxes which the seller had plus half box more. A second customer comes and purchases half the remaining number of boxes plus half a box. After this the seller is left with no chocolate boxes. How many chocolate boxes the seller had initially?

Explanation:-

The best way to go through the options
Let there are initially 3 boxes then,
1^st customer gets = $$\frac{3}{2}$$ + $$\frac{1}{2}$$ = 2
Remaining boxes = 3 - 2 = 1
2^nd customer = $$\frac{1}{2}$$ + $$\frac{1}{2}$$ = 1
So, option 2 is correct.