A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
  • 112
  • 216
  • 324
  • 418
Answer:- 1
Explanation:-

Solution:
Let he has solved correctly X no. of sums. Therefore incorrect no. of sums = 2X .
Now,
X + 2X = 48
3X = 48
X = 16 sums he has done correctly.

Post your Comments

Your comments will be displayed only after manual approval.

Test
Classes
E-Book