India’s No.1 Educational Platform For UPSC,PSC And All Competitive Exam

Download Our App

(12)³ X 6⁴ X 432^-1 = ?

15184
25060
35148
45084

Answer:- 1

Explanation:-

Solution:

\begin{aligned} Given Exp . \\ = \frac{{(12)}^{3} \times 6^{4}}{432} \\ = \frac{{(12)}^{3} \times 6^{4}}{12 \times 6^{2}} \\ = {(12)}^{2} \times 6^{2} \\ = {(72)}^{2} \\ = 5184 \end{aligned}

$\eqalign{ & {\text{Given}}\,{\text{Exp}}{\text{.}} \cr & = \frac{{{{\left( {12} \right)}^3} \times {6^4}}}{{432}} \cr & = \frac{{{{\left( {12} \right)}^3} \times {6^4}}}{{12 \times {6^2}}} \cr & = {\left( {12} \right)^2} \times {6^2} \cr & = {\left( {72} \right)^2} \cr & = 5184 \cr}$

Workspace Report

Post your Comments

", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

\begin{aligned} Given Exp . \\ = \frac{{(12)}^{3} \times 6^{4}}{432} \\ = \frac{{(12)}^{3} \times 6^{4}}{12 \times 6^{2}} \\ = {(12)}^{2} \times 6^{2} \\ = {(72)}^{2} \\ = 5184 \end{aligned}

$\eqalign{ & {\text{Given}}\,{\text{Exp}}{\text{.}} \cr & = \frac{{{{\left( {12} \right)}^3} \times {6^4}}}{{432}} \cr & = \frac{{{{\left( {12} \right)}^3} \times {6^4}}}{{12 \times {6^2}}} \cr & = {\left( {12} \right)^2} \times {6^2} \cr & = {\left( {72} \right)^2} \cr & = 5184 \cr}$ ", "dateCreated": "7/24/2019 10:09:12 AM" } }

Test

Classes

E-Book