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If two numbers are respectively 30% and 40% more than a third number, what percent is the first of the second?

1 $92 \frac{6}{7} %$ $92\frac{6}{7}\%$
2 $84 \frac{4}{5} %$ $84\frac{4}{5}\%$
380%
475%

Answer:- 1

Explanation:-

Solution:

Let the third number be 100. Then,
1^st number = 130
2^nd number = 140
% 1^st number to the 2^nd number =

\frac{130 \times 100}{140}

$\frac{{130 \times 100}}{{140}}$

= \frac{650}{7} = 92 \frac{6}{7} %

$= \frac{{650}}{7} = 92\frac{6}{7}\%$

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= \frac{650}{7} = 92 \frac{6}{7} %

$= \frac{{650}}{7} = 92\frac{6}{7}\%$
", "dateCreated": "7/24/2019 10:09:12 AM", "author": { "@type": "Person", "name": "Nitin Sir" } }, "suggestedAnswer": { "@type": "Answer", "text": "

Solution:

Let the third number be 100. Then,
1^st number = 130
2^nd number = 140
% 1^st number to the 2^nd number =

\frac{130 \times 100}{140}

$\frac{{130 \times 100}}{{140}}$

= \frac{650}{7} = 92 \frac{6}{7} %

$= \frac{{650}}{7} = 92\frac{6}{7}\%$
", "dateCreated": "7/24/2019 10:09:12 AM" } }

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